Conservation_Of_Energy

Conservation Of Energy Conservation of Energy Objective: The objective is to find the spring constant, and to find the potential energy of the system. Apparatus: Data: M (Kg) X (m) F (N) K .3 .10250 2.9434 28.71 .4 .13750 3.924 28.54 .5 .17500 4.905 28.03 .6 .21250 5.886 27.70 .7 .25375 6.876 27.06 Slope= 26N/m % Error= 7.723% Standard Deviation = .4425 N/m Conservation of Energy (Falling) X1 X2 ΔPEg ΔPEs % of error .04 .462 2.0678 2.967 43.49 % .08 .431 1.7199 2.512 46.06 % .12 .392 1.3328 1.950 46.31 % .16 .351 .9359 1.367 46.06 % X1 X2 ΔPEg ΔPEs % of error .215 .1301 .416 0.386 1.248 % .255 .085 .833 0.772 7.323 % .295 .055 1.176 1.158 1.531 % .335 .019 1.568 1.548 1.276 % Calculations K=F/x 2.9434N/.1025m= 28.71 N/m F=mg .30kg*9.8m/s2 = 2.9434N Percent error between ΔPEg and ΔPEs ((2.967 – 2.0678)/2.0678)*100 = 43.49 % ΔPEg = mg(X2 – X1) = (.5kg)(9.8m/s2)(.462m - .04m) = 2.0678J ΔPEs = (½)k(X22 - X22) = (½)(28.008)(.4622 -.042) = 2.967J Standard Deviation √[(∑(k-kave)2/(n-1)] =√[(∑(28.71-28.008)2+(28.54-28.008)2+…)/(4)] =.4425N/m Question: Do the data indicate that the mechanical energy is conserved for this system' The data indicated for the mechanical energy is conserved for this system. This is not found from the high error between the change in spring potential and gravitational potential that was not conserved. The energy, error, spring, conserved, system, potential, data, between, weights, travels, standard, released, purpose, percent, n/m, mechanical, measuring, mass, lab, gravitational, found, find, errors, equilibrium, distance, deviation, conservation